预估题目难度是中等偏下的，只要好好看题，就知道这道题是一道很简单的很单纯的ifelse的一个判断。把每一种情况自己考虑清楚答案就出来了，具体每种情况可以自己慢慢把题目读一遍。

#include<bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;

void solve()
{
	int n;
	cin >> n;
	if(n == 1) {
		int x, y, z;
		cin >> x >> y >> z;
		if(z == 1) {
			if(x == y) cout << "No" << endl;
			else cout << "Yes" << endl;
		}
		else if(z == 0) cout << "Yes" << endl;
	}
	else if(n == 2) {
		int x, y, z, xx, yy, zz;
		cin >> x >> y >> z >> xx >> yy >> zz;
		if(z == 1) {
			if(x == y) cout << "No" << endl;
			else if(x != y) {
				if(zz == 1) {
					if(xx == yy) cout << "No" << endl;
					else if(xx != yy) {
						if(xx == y && yy == x) cout << "No" << endl;
						else cout << "Yes" << endl;
					}
				}
				else if(zz == 0) {
					if(xx == x && yy == y) cout << "No" << endl;
					else cout << "Yes" << endl;
				}
			}
		}
		else if(z == 0) {
			if(zz == 1) {
				if(xx == yy) cout << "No" << endl;
				else if(xx != yy) {
					if(xx == x && yy == y) cout << "No" << endl;
					else cout << "Yes" << endl;
				}
			}
			else if(zz == 0) cout << "Yes" << endl;
		}
	}
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);

    int _T_ = 1;
	cin >> _T_;

    while(_T_ --) solve();
    return 0;
}