7 solutions
-
1
稍微取巧一点的办法
#include <stdio.h> int main() { int n; scanf("%d",&n); getchar(); char l; for(int x=0;x<n;x++){ char a,b,c; scanf("%c%c%c",&a,&b,&c); if(a>b){ l=a; a=b; b=l; } if(a>c){ l=a; a=c; c=l; } if(b>c){ l=b; b=c; c=l; } printf("%c %c %c\n",a,b,c); getchar(); } return 0; }
Information
- ID
- 120
- Time
- 3000ms
- Memory
- 128MiB
- Difficulty
- 7
- Tags
- # Submissions
- 2666
- Accepted
- 632
- Uploaded By