10 solutions
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2
python大法好,拒绝手写结构体排序,从我做起(实际上是py自带的关键字排序)。
m = int(input()) for _ in range(m): n = int(input()) act = [] act_num = 1 for __ in range(n): lst = list(map(int, input().split( ))) act.append(lst) act.sort(key = lambda x : x[1]) pointer = 0 for i in range(1, n): if act[i][0] > act[pointer][1]: act_num += 1 pointer = i print(act_num)
Information
- ID
- 124
- Time
- 3000ms
- Memory
- 128MiB
- Difficulty
- 8
- Tags
- (None)
- # Submissions
- 1952
- Accepted
- 265
- Uploaded By