15 solutions

  • 2
    @ 2023-10-8 10:30:58

    #include <stdio.h> int main() { int n,i,cont,j,k; cont=0; scanf("%d",&n); for (i=1;i<=n;i++) { j=i%10; k=i/10; while(i!=99) { if(j9||k9){cont++; } break; } if (i==99){ cont+=2; } }

    printf("%d",cont);
    
    return 0;
    

    }

    Information

    ID
    33
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    7
    Tags
    # Submissions
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    Accepted
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