13 solutions
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2
#include<stdio.h> int main(){ int a[8][3],sum[8]={0},m=8,day; for(int i=1;i<8;i++){ for(int j=1;j<3;j++){ scanf("%2d",&a[i][j]); printf("\n"); } }
for(int i=1;i<8;i++){ for(int j=1;j<3;j++){ sum[i]+=a[i][j]; } } for(int i=1;i<8;i++){ if(sum[i]>m){ m=sum[i]; day=i; } } if(m>8){ printf("%d",day); }else{ printf("0"); } return 0;}
Information
- ID
- 44
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- (None)
- # Submissions
- 4858
- Accepted
- 1012
- Uploaded By