思路：判断西瓜重量 n，若 n 是奇数或 n等于2，则无法分成两个偶数部分；若 n 是​大于 2 的偶数​，则可以分成两个偶数部分。

#include<iostream>
using namespace std;
int main()
{
    int n; cin>>n;
    if(n % 2 == 1 || n == 2)
    cout << "NO, you can't divide the watermelon into two even parts." << endl;
    else
    cout << "YES, you can divide the watermelon into two even parts." << endl;
    return 0;
}