1 条题解
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0
int main() { int t; long long x=0,y=0,z=0; int top=0,r=1,l=4,u=2,d=5,b=3; scanf("%d",&t); while(t--){ char s[2]; int n; scanf("%s %d",s,&n); char a = s[0]; if( a=='b'){ int re=l; l=r; r=re; re=top; top=b; b=re; }else if( a=='l'){ int re=top; top=l; l=b; b=r; r=re; }else if( a=='r'){ int re=top; top=r; r=b; b=l; l=re; }else if( a=='u'){ int re=top; top=u; u=b; b=d; d=re; }else if( a=='d'){ int re=top; top=d; d=b; b=u; u=re; } if(top==0){ x+=n; }else if(top==1){ y+=n; }else if(top==2){ z+=n; }else if(top==3){ x-=n; }else if(top==4){ y-=n; }else if(top==5){ z-=n; } // printf("%lld %lld %lld %d\n",x,y,z,top); } printf("%lld %lld %lld %d",x,y,z,top); return 0; }
- 1
信息
- ID
- 240
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- (无)
- 递交数
- 196
- 已通过
- 10
- 上传者