1 条题解
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思路：判断西瓜重量
n，若n是奇数或n等于2，则无法分成两个偶数部分；若n是大于 2 的偶数，则可以分成两个偶数部分。-
morgen
@ 2025-10-12 21:07:42
#include<iostream> using namespace std; int main() { int n; cin>>n; if(n % 2 == 1 || n == 2) cout << "NO, you can't divide the watermelon into two even parts." << endl; else cout << "YES, you can divide the watermelon into two even parts." << endl; return 0; }
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