#include <bits/stdc++.h>
using namespace std;
#define int long long
void solve() {
    int a,b,c;
    cin >> a >> b >> c;
    // 若三幅牌的总数不是3的倍数，直接输出 "haha"
    if((a + b + c) % 3){
        cout << "haha" << '\n';
        return;
    }else{
        int x = (a + b + c) / 3;
        // 若两人手中持牌数都不大于 X，则一定可以
        if(a <= x && b <= x){
            cout << "good" << '\n';
        }else{
            cout << "haha" << '\n';
        }
    }
}
signed main() {
    ios::sync_with_stdio(0);
    cin.tie(0),cout.tie(0);
    int T = 1;
    cin >> T;
    while (T--)
        solve();
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll N=2e5+5;
#define fs1(i,a,b) for(ll i=a;i<=b;i++)
#define fj1(i,a,b) for(ll i=b;i>=a;i--)
#define fs2(i,a,b) for(ll i=a;i<b;i++)
#define fj2(i,a,b) for(ll i=b-1;i>=a;i--)
#define pq priority_queue
#define pll pair<ll,ll> 
ll t;
int main(){
	ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
	cin>>t;
	while(t--){
		ll a,b,c;
		cin>>a>>b>>c;
		ll s=a+b+c;
		ll r=s/3;
		if(s%3==0&&r>=a&&r>=b) cout<<"good"<<'\n';
		else cout<<"haha"<<'\n';
	}	
	return 0;
}