这个题的数据是三位数，你只需要设三个未知数就可以解决，当然你设置一个程序，让任何数都能进行判断，也是可以的，能够提高编程能力

#include<stdio.h> int main() { int n; while(scanf("%d",&n)&&n!=0){ int a,b,c; a=n%10; b=n/10%10; c=n/100; if(aaa+bbb+ccc==n){ printf("Yes\n"); } else{ printf("No\n"); } } return 0; }

算术题

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    int a = 1;
    while (1) {
        cin >> a;
        if (a == 0) break;
        if (pow(a / 100, 3) + pow(a / 10 % 10, 3) + pow(a % 10, 3) == a) {
            cout << "Yes" << endl;
        }
        else cout << "No" << endl;
    }
}

#include<iostream>
using namespace std;
int main(){
int n;
while(1){
cin>>n;
if(n==0){
return 0;
}
int a,b,c;
a=n%10;b=n/10%10;c=n/100;
if(n==a*a*a+b*b*b+c*c*c){
cout<<"Yes"<<endl;
}else{
cout<<"No"<<endl;
}
}
}