#include <stdio.h>
int main() {
	int k,x,y,n;
	scanf("%d",&n);
	while(n--) {
		scanf("%d",&k);
		for(x=(k+1); x<=2*k; x++) {
			y=(k*x)/(x-k);
			if((k*x)%(x-k)==0) {
				y=(k*x)/(x-k);
				printf("1/%d=1/%d+1/%d\n",k,y,x);
			}
		}
	}
	return 0;
}

属于是屎山代码了😅

from math import sqrt,ceil,gcd,log;re=lambda:map(int,input().strip().split())

t, = re()
for _ in range(t):
    k, = re()
    for y in range(2, 2 * k + 1):
        try:
            if (k * y) % (y - k) == 0:
                x = (k * y) // (y - k)
            if x > 0 and k * (x + y) == x * y:
                print(f"1/{k}=1/{x}+1/{y}")
        except:
            pass

#include<stdio.h>

int main(){ int n; scanf("%d",&n); while(n--){ int x; scanf("%d",&x); for(int i=x+1;i<=2x;i++){ for(int k=i;k<ii;k++){ if(1/(x1.0)==(i+k)/(ik*1.0)){ printf("1/%d=1/%d+1/%d\n",x,k,i); } } } } return 0; }

#include <stdio.h>
int main() {
	int n;
	scanf("%d",&n);
	while(n--) {
        int k,x,j;
		scanf("%d",&k);
        for(x=k+1;x<=2*k;x++){
            j=k*x/(x-k);
            if(j*x==k*x+k*j){
            printf("1/%d=1/%d+1/%d",k,j,x);
            printf("\n");
            }
        }	
	}
	return 0;
}