将这些数分成几行（斜着 如1行只有 1 1 2行有 1 2

和 2 1）然后计算出在第几行，最后分成奇偶情况

讨论，很容易就能找出规律
```#include<stdio.h>
int main()
{
	int m;
	scanf("%d",&m);
	while(m--)
	{
		int n;
		scanf("%d",&n);
		int sum=0;
		int d1=1;
		int i;
		while(sum<n)
		{
			for(i=1;i<=d1;i++)
			{
				sum++;
				if(sum==n)
				break;
			}
			if(sum<n)
			{
				d1++;
			}
		}
		if(d1%2==0)
		printf("%d/%d\n",i,d1-i+1);
		else
		printf("%d/%d\n",d1-i+1,i);
	}
}
``````
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