5 条题解

  • 1
    @ 2024-10-14 21:27:22

    eg: 98886-90000=8886; 往这里想就很简单啦!👀️ #include <stdio.h>

    int main()

    {

    int m;

    scanf("%d",&m);

    while(m--){

    int a;

    scanf("%d",&a);

    int sum=0;

    int b=a;

    int k;

    for(;;){

    b=b/10;

    if(b!=0){

    sum++;

    k=b;

    }else if(b==0){

    break;

    }

    }

    int z=k;

    for(int l=0;l<sum;l++){

    z*=10;

    }

    int c=a-z;

    printf("%d",c);

    printf("\n");

    }

    return 0;

    }

    • 0
      @ 2025-10-15 1:24:51
      #include<iostream>
      #include<string.h>
      
      using namespace std;
      int main(){
          int M;
          cin>>M;
          while(M--){
              char w[8];
              cin>>w;
              int len=strlen(w);
              int g=1;
              for(int j=1;j<len;j++){
                  if(w[j]=='0'&&g!=0){continue;}
                  cout<<w[j];g=0;
              }if(g==1){cout<<"0";}
              cout<<'\n'; 
      
          }
          return 0;
      }
      
      • 0
        @ 2025-9-13 21:58:28

        依旧python语法题

        for _ in range(int(input())):print(int(input()[1:]))
        
        • 0
          @ 2024-12-10 1:22:20

          #include<stdio.h> #include<string.h>

          int main() { int t; scanf("%d", &t); while (t--) { char s[100]; int a[100]; scanf("%s", s); int n = strlen(s); for (int k = 0; k < n; k++) { a[k] = s[k] - '0'; } int sum = 1, ans=1; for (int k = 1; k < n; k++) {

          if (a[k] == 0) { sum ++; } } for (int k = 1; k < n; k++) { if (a[k] != 0) { ans = k; break; }

          } if (sum == n ) { printf("0\n"); } else { for (int k = ans; k < n; k++) { printf("%d", a[k]); } printf("\n"); }

          } return 0;

          }

          • 0
            @ 2023-9-28 9:03:43
            #include <stdio.h>
            #include <string.h>
            #define MAXSIZE 1000000+1
            int main()
            {
            	char ch[MAXSIZE]={'\0'};
                int Cases;
                scanf("%d",&Cases);
                while(Cases--)
                {
            		scanf("%s",ch);
            		int len=strlen(ch);
            		int i=1;
            		while((ch[i]-'0')==0)
            		{
            			i++;
            		}
            		if(i==len)
            			printf("0\n");
            		else
            		{
            			for(;i<len;i++)
            			{
            				printf("%c",ch[i]);
            			}
            			printf("\n");
            		}
                }
            	return 0;
            }
            
            • 1

            信息

            ID
            159
            时间
            3000ms
            内存
            128MiB
            难度
            5
            标签
            (无)
            递交数
            642
            已通过
            271
            上传者