6 solutions
-
0
#include<stdio.h> #include<string.h>
int main() { int t; scanf("%d", &t); while (t--) { char s[100]; int a[100]; scanf("%s", s); int n = strlen(s); for (int k = 0; k < n; k++) { a[k] = s[k] - '0'; } int sum = 1, ans=1; for (int k = 1; k < n; k++) {
if (a[k] == 0) { sum ++; } } for (int k = 1; k < n; k++) { if (a[k] != 0) { ans = k; break; }
} if (sum == n ) { printf("0\n"); } else { for (int k = ans; k < n; k++) { printf("%d", a[k]); } printf("\n"); }
} return 0;
}
Information
- ID
- 159
- Time
- 3000ms
- Memory
- 128MiB
- Difficulty
- 4
- Tags
- (None)
- # Submissions
- 722
- Accepted
- 310
- Uploaded By