6 solutions

  • 0
    @ 2024-12-10 1:22:20

    #include<stdio.h> #include<string.h>

    int main() { int t; scanf("%d", &t); while (t--) { char s[100]; int a[100]; scanf("%s", s); int n = strlen(s); for (int k = 0; k < n; k++) { a[k] = s[k] - '0'; } int sum = 1, ans=1; for (int k = 1; k < n; k++) {

    if (a[k] == 0) { sum ++; } } for (int k = 1; k < n; k++) { if (a[k] != 0) { ans = k; break; }

    } if (sum == n ) { printf("0\n"); } else { for (int k = ans; k < n; k++) { printf("%d", a[k]); } printf("\n"); }

    } return 0;

    }

    Information

    ID
    159
    Time
    3000ms
    Memory
    128MiB
    Difficulty
    4
    Tags
    (None)
    # Submissions
    722
    Accepted
    310
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