#include<stdio.h>

int main(){

int t,n,a,x=1;

scanf("%d",&t);

while(t--){

scanf("%d",&n);

int sum=0;

for(int i=1;i<=n;i++){

a=i+1;

sum=sum+i*((a*a+a)/2);

}

printf("%d %d %d\n",x,n,sum);

x++;

}

return 0;

}

#define _CRT_SECURE_NO_WARNINGS #include<stdio.h> int arr[10001];//存储前n个数的和 void nat() { int num = 0; int j = 1; for (int i = 1; i < 10001; i++) { num += i; arr[j++] = num;//j表示前j个自然数的和 } }

int add(int a) { nat(); int sum = 0; for (int i = 1; i < a+1 ; i++) { sum += i * arr[i + 1]; } return sum; }

int main() { int n; int hao = 0; scanf("%d", &n); while (n--) { hao++; int a; scanf("%d", &a); printf("%d %d %d\n",hao,a, add(a)); } return 0; }

#include <stdio.h> 
int fun2(int k){
	int T;
	T=k*(k+1)/2;
	return T;}

int fun(int n){
	int sum=0;
	for(;n>0;n--)
	sum+=n*fun2(n+1);
	return sum;}

int main()
{
	int N;
	scanf("%d",&N);
    int n[N+5];
	for (int i=0;i<N;i++)
	scanf("%d",&n[i]);
    for (int i=0;i<N;i++)
    printf("%d %d %d\n",i+1,n[i],fun(n[i]));
}