#include<stdio.h>
#include<math.h>
int main(){
    double r;
    double s;
    double pi = 3.1415926;
    while(scanf("%lf",&r) != EOF){
      s = 4*pi*pow(r,3)/3;//圆的体积公式
      s = floor(s+0.5);//四舍五入
      printf("%.0lf\n",s); 
    }
}

#include <stdio.h>
#define PI 3.1415926
int main()
{double a;
while(scanf("%lf",&a)!=EOF){
printf("%.0lf\n",4*PI*a*a*a/3);}
return 0;}

from math import sqrt,ceil,gcd,log;re=lambda:map(int,input().strip().split())
while True:
    try:
        r = float(input())
        print(f"{3.1415926*4/3*r*r*r:.0f}")
    except:
        break

就那样嘿嘿👀️ ❤️ 👀️ 那个下面printf里面是4乘PI×a的三次方÷3

#include <stdio.h>

#define PI 3.1415926

int main()

{

double a;

while(scanf("%lf",&a)!=EOF){

printf("%.0lf\n",4PIaaa/3);

}

return 0;

}

#include<stdio.h> #include<math.h> int main(){ double m; while(scanf("%lf",&m)!=EOF) { double v=4.0/3.03.1415926pow(3,m); int r = v+0.5; printf("%d\n",r); }

return 0;

}