17 条题解

  • 3
    @ 2023-8-9 21:04:46
    #include<stdio.h>
    int main()
    {
        int abcd,n,a,b,c,d;
        //1000<=abcd<=9999
        scanf("%d",&abcd);
        d=abcd%10;
        c=abcd/10%10;
        b=abcd/100%10;
        a=abcd/1000;
        n=d*1000+c*100+b*10+a;
        printf("%d",n);
        return 0;
    }
    
    • 1
      @ 2024-10-9 21:18:47

      #include<stdio.h> int main() { int a,b,c,d,abcd,sum;//简单易懂; scanf("%d",&abcd); a=abcd/1000; b=(abcd-a1000)/100; c=(abcd-a1000-b100)/10; d=(abcd-a1000-b100-c10); sum=d1000+c100+b*10+a; printf("%d",sum); return 0; }

      • 1
        @ 2024-7-25 11:48:18

        #include <stdio.h>

        int main() { int n;

        scanf("%d", &n);

        // 反转数字 int reversed = 0; while (n > 0) { reversed = reversed * 10 + n % 10; // 取出最后一位并加入反转数 n /= 10; // 去掉最后一位 }

        // 输出反转后的值 printf("%d\n", reversed);

        return 0; }

        • 1
          @ 2023-8-25 8:48:09

          #include <stdio.h> int main() { int x; scanf("%d",&x); int a; int b=0; while(x>0) { a=x%10; b=b*10+a; x=x/10; } printf("%d",b); return 0; }

          • 1
            @ 2022-10-11 16:59:30

            #include <stdio.h> int main() { int m, a, b, c, d; while(scanf("%d",&m)!=EOF) { if(m>=1000&&m<=9999) { a = m/1000; b = m/100%10; c = m/10%10; d = m%10; if(d==0) printf("%d\n",100c+10b+a); else printf("%d\n",1000d+100c+10*b+a); } } return 0; }

            • 0
              @ 2026-4-17 21:06:42

              #include <stdio.h>

              int main() { int a; int i=1; scanf("%d",&a); while(i<=4){ printf("%d",a%10); a=a/10; i++; } return 0; }

              • 0
                @ 2025-11-15 23:26:46
                #include<stdio.h>
                int main(){
                int a,b,c,d,n,s;
                scanf("%d",&n);
                a=n/1000;b=n%1000/100;c=n%100/10;d=n%10;
                s=d*1000+c*100+b*10+a;
                printf("%d",s);
                return 0;
                }
                
                • 0
                  @ 2025-11-10 17:37:01

                  #include<iostream> #include<stack> using namespace std; int main(){ int n; cin>>n; stack<int> st; while(n>0){ int yu=n%10; st.push(yu); n=n/10; } while(st.top()==0){ st.pop(); } int t=1; while(!st.empty()){ n+=st.top()t; t=10; st.pop(); } cout<<n; }

                  • 0
                    @ 2025-9-25 21:00:57

                    #include<stdio.h> int main(){ int sb ,c; ** c=0;** scanf("%d",&sb); ** while(sb!=0){c=c*10+sb%10;sb/=10;}** ** //TODO ** printf("%d",c);


                    return 0; }

                    • 0
                      @ 2024-7-25 11:49:30

                      #include <stdio.h>

                      int main() { int n;

                      scanf("%d", &n);

                      // 反转数字 int reversed = 0; while (n > 0) { reversed = reversed * 10 + n % 10; // 取出最后一位并加入反转数 n /= 10; // 去掉最后一位 }

                      // 输出反转后的值 printf("%d\n", reversed);

                      return 0;

                      }

                      • 0
                        @ 2024-4-24 22:11:15
                        #include <stdio.h>
                        
                        #include "math.h"
                        int main()
                        {
                            int nb(int a);
                            int a,n,i;
                            scanf("%d",&a);
                            n=nb(a);
                            i=n;
                            int num[n],b=a;
                            while (i>0)
                            {
                                num[i]=(int)(b/(int)pow(10,i-1));
                                b=b-num[i]*(int)pow(10,i-1);
                                i--;
                            }
                        
                            i=1;
                            int c;
                            while (i<=n)
                            {
                                c+=num[i]*pow(10,n-i+1)/10;
                                i++;
                            }
                            printf("%d",c);
                        
                        
                            return 0;
                        }
                        
                        int nb(int a)
                        {
                            int nb=0,ns=1;
                            while(a/ns!=0)
                            {
                                nb++;
                                ns=10*ns;
                            }
                            return nb;
                        }
                        //
                        
                        • 0
                          @ 2022-10-8 23:12:00
                          #include<stdio.h>
                          int main()
                          {
                              int abcd,n,a,b,c,d;
                              //1000<=abcd<=9999
                              scanf("%d",&abcd);
                              d=abcd%10;
                              c=abcd/10%10;
                              b=abcd/100%10;
                              a=abcd/1000;
                              n=d*1000+c*100+b*10+a;
                              printf("%d",n);
                              return 0;
                          }
                          
                          
                          • 0
                            @ 2022-10-5 20:15:46

                            #include<stdio.h> int main(){ int a,b,c,d,N; scanf("%d",&N); a=N/1000; b=N/100%10; c=N/10%10; d=N/1%10; printf("%d",d1000+c100+b*10+a); return 0;

                            }
                            
                            • 0
                              @ 2022-10-3 9:19:47
                              #include<stdio.h>
                              int main(){
                                  int n,a,b,c,d,sum=0;
                                  scanf("%d",&n);
                                  a=n%10;
                                  b=n/10%10;
                                  c=n/100%10;
                                  d=n/1000;
                                  sum=a*1000+b*100+c*10+d;
                                  printf("%d",sum);
                                  return 0;
                              }
                              
                              • 0
                                @ 2022-9-30 9:01:51
                                #include<bits/stdc++.h>
                                using namespace std;
                                int main()
                                {
                                	int s, a;
                                	while(cin >> s)
                                	{
                                		a = s / 1000;//ge
                                		a += s / 100 % 10 * 10;//shi
                                		a += s / 10 % 10 * 100;//bai
                                		a += s % 10 * 1000;//qian
                                		cout << a << endl;
                                	}
                                	return 0;
                                }
                                
                                
                                
                                • 0
                                  @ 2022-9-27 20:09:50

                                  #include<stdio.h>

                                  int main(){

                                  int n,a,b=0;

                                  scanf("%d",&n);

                                  while(n!=0){

                                  a=n%10;

                                  b=(b*10)+a;

                                  n=n/10; } printf("%d",b);

                                  return 0; }

                                  • 0
                                    @ 2022-9-27 16:13:40

                                    #include<stdio.h> int main() { int n; int a,b,c,d; scanf("%d",&n); a=n%10; b=(n%100)/10; c=(n%1000)/100; d=n/1000; printf("%d",a1000+b100+c*10+d); return 0; }

                                    • 1

                                    信息

                                    ID
                                    27
                                    时间
                                    1000ms
                                    内存
                                    128MiB
                                    难度
                                    6
                                    标签
                                    递交数
                                    6384
                                    已通过
                                    2108
                                    上传者