11 条题解

  • 1
    @ 2024-4-24 22:12:23
    #include <stdio.h>
    int main()
    {
        int n,i=1;
        double a,b,c=1.0;
        scanf("%d",&n);
        while(i<=n)
        {
            b=c/i;
            a=a+b;
            c=-c;
            i++;
        }
        printf("%.1lf",a);
        return 0;
    }
    //
    
    • 0
      @ 2025-10-2 10:09:04
      #include <stdio.h>
      int main()
      {
          int a,b=1,c=1;
          double d=0;
          scanf("%d",&a);
          while (a--){
              d+=b*1.0/c;
              b=-b;
              c++;
          }printf("%.1lf",d);
      }
      
      • 0
        @ 2025-9-25 22:45:48

        #include<stdio.h> int main(){ int sb,a=1; double i,sum ; scanf("%d",&sb); ** for(i=1;i<=sb;i++)** ** {sum+=a/i; ** a=-a;


        **}**
        

        ** printf("%.1f",sum);**


        return 0; }

        • 0
          @ 2025-8-19 20:37:38

          #include<stdio.h> int main() { int N,i=1; scanf("%d",&N); double b=0; while(i<=N) { if(i%2==0) { b=b-1.0/i; i++; } else { b=b+1.0/i; i++; }

          }
          printf("%.1f",b);
          return 0;
          

          }

          • 0
            @ 2024-10-11 21:49:00

            #include<Stdio.h> int main() { int i,n=0; float sum=0; scanf("%d",&n); for(i=1;i<=n;i++) { if(i%2==0) sum=sum+1.0*(-1)/i; if(i%2!=0) sum=sum+1.0/i; } printf("%.1f",sum); }

            • 0
              @ 2023-9-19 19:19:10
              #include <stdio.h> 
              int main() 
              {
                  int i,n=0;
                  float sum=0;
                  scanf("%d",&n);
                  for(i= 1;i<=n;i++)
                  {
                      if(i%2==0)
                      sum=sum+1.0*(-1)/i;
                      if(i%2!=0)
                      sum=sum+1.0/i;
                      }
                  printf("%.1f",sum);
                  return 0;
              }
              
              • 0
                @ 2023-8-21 19:19:12

                #include <stdio.h> int main () { int i,sign; sign=1; int n; scanf("%d",&n); double m=0.0; for ( i=1;i<=n;i++) { m+=sign*1.0/i; sign=-sign; } printf("%.1f",m); return 0; }

                • 0
                  @ 2023-8-14 15:24:18

                  #include<iostream>#include<iomanip> using namespace std; int main() {int i,n,a;

                  double sum;cin>>n;for(i=1;i<=n;i++)

                  {

                  //为什么必须将i的临时值赋给一个变量,对啊可以不用赋值

                  if(i%2==0)

                  sum=sum-(1.0/i);

                  else sum=sum+(1.0/i);

                  } cout << fixed << setprecision(1) << sum << endl;

                  return 0;}

                  • 0
                    @ 2022-10-6 10:27:02

                    #include<stdio.h> int main(){ int n; double a; scanf("%d",&n); for(int i=1;i<=n;i++){ if(i%2!=0){ a=a+1.0/i; } else if(i%2==0){ a=a-1.0/i; } } printf("%.1lf",a); return 0; }

                    • 0
                      @ 2022-9-27 16:21:21

                      #include<stdio.h>

                      int main(){

                      int n;

                      double sum=0,a=1;

                      scanf("%d",&n);

                      for(int i=1;i<=n;i++){

                      sum+=a/i;

                      a=-a;

                      } printf("%.1lf",sum);

                      return 0; }

                      • 0
                        @ 2022-9-26 16:33:48

                        #include<stdio.h>

                        int main(void)

                        { int n,i,s; scanf("%d",&n); float sum=0;

                        for(i=1;i<=n;i++){ s=i; if(s%2==0){ s=-i; }

                        sum=sum+(1.0/s); }

                        printf("%.1f",sum);

                        return 0;

                        }

                        • 1

                        信息

                        ID
                        31
                        时间
                        1000ms
                        内存
                        128MiB
                        难度
                        6
                        标签
                        递交数
                        5331
                        已通过
                        1678
                        上传者