两三角形对应边相等且都是直角三角形

from math import sqrt,ceil,gcd,log;re=lambda:map(int,input().strip().split())
a = list(re())
b = list(re())
a.sort()
b.sort()
if a == b and a[0] ** 2 + a[1] ** 2 == a[2] ** 2:
    print("Yes")
else:
    print("No")