这个为什么不可以？ #include<stdio.h> int main() { int n,x,y; scanf("%d %d %d",&n,&x,&y); (int)n=n-y*1.0/x; printf("%d",n); return 0;

}

#include <stdio.h>
int main()
{
    
    float b,c;
    int a;
    scanf("%d%f%f",&a,&b,&c);
    int n=a-c/b;
    printf("%d",n);
    return 0;
}//

#include<stdio.h> int main() { int n,x,y,sum; scanf("%d %d %d",&n,&x,&y); if(y%x==0) sum=n-y/x; else {sum=n-y/x-1; } printf("%d",sum); return 0; }

#include <stdio.h> 
int main()
{
    float x,y,n,c;
    scanf("%f%f%f",&n,&x,&y);
    c=y/x;
    n=n-c;
    printf("%d",(int)n);
    return 0;
}

#include <stdio.h>

int main() { int a = 0; int b = 0; int c = 0; scanf("%d %d %d", &a, &b, &c); int x; x = a - (1.0 /b)* c; printf("%d", x); return 0; }//看了其他人的题解我感觉我这个有点问题————-----------

#include<stdio.h>
int main(){
    int n,x,y;
    scanf("%d %d %d",&n,&x,&y);
    if(y % x == 0){
       printf("%d", n - (y / x));
    } else {
        printf("%d",n - ((y / x) + 1));
    }
    return 0;
}

#include<stdio.h>
int main(){
    int n,x,y;
    scanf("%d %d %d",&n,&x,&y);
    if(y % x == 0){
       printf("%d", n - (y / x));
    } else {
        printf("%d",n - ((y / x) + 1));
    }
    return 0;
}