10 条题解

  • 1
    @ 2023-10-3 10:57:42
    #include <stdio.h>
    int m[1000005];
    int main()
    {
    	int a,b;
        int c=0;
        scanf("%d %d ",&a,&b);
        m[1]=1;
        m[2]=1;
        for(int i=3;;i++)
        {
            m[i]=m[i-1]+m[i-2];
            if(m[1]==a||m[2]==a)
            {
                ++c;
                c*=2;
            }
            if(a<=m[i]&&m[i]<=b)
            {
                c++;
            }
            if(m[i]>b)
            {
                break;
            }
    
        }
        printf("%d",c);
        return 0;
    }
    
    
    • 1
      @ 2023-8-29 23:35:24
      #include
      int main()
      {
      	int i=0,a,b,f1=1,f2=1;
      	scanf("%d%d",&a,&b);
      	for(;;)
      	{
      		f1=f1+f2;
      		if(f1>=a&&f1<=b)
      		i++;
      		f2=f1+f2;
      		if(f2>=a&&f2<=b)
      		i++;
      		if(f1>b||f2>b)
      		break;
      	}
      	printf("%d",i);
      	return 0;
      }
      
      • 1
        @ 2023-8-23 16:25:41

        空间换时间,提前导出一个斐波那契数列数组就好。

        #include <cstdio>
        
        int Fibo[31] = {1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040, 1346269};
        //数据范围在1000000以内,故导出这个范围内的斐波那契数列数组,多导出一位防止index溢出。
        
        int main(){
            int a, b, ans = 0;
            scanf("%d %d", &a, &b);
            for(int i = 0; i <= 30; i++){
                if((a <= Fibo[i])&&(Fibo[i] <= b)){
                    ans++;
                }
            }
            printf("%d", ans);
        }
        
        • 0
          @ 2024-11-8 15:35:12

          #include<iostream> using namespace std; int cun[1000]; int cnt; void feibo() { cun[1]=1,cun[2]=1; for(int i=3;i<1000;i++){ cun[i]=cun[i-1]+cun[i-2]; } }

          int main() { ios::sync_with_stdio(0),cin.tie(0),cout.tie(0); int a,b; cin >> a >> b ; feibo(); for(int i=1;i<1000;i++){ if(cun[i]>b) break; if(cun[i]>=a && cun[i]<=b) cnt++; } cout << cnt; return 0; }

          • 0
            @ 2024-10-12 16:25:41

            #include<stdio.h>

            int main() { int a,b,c=0; scanf("%d %d",&a,&b); inti=1,j=0,k=1,x=1; while(i>0){ if(i<=1){ j=i; }else{ j=k+x; k=x; x=j; } if(j>=a&&j<=b){ c++; }else if(j>b){ break; } i++; } printf("%d",c);

            return 0;

            }

            • 0
              @ 2024-10-2 14:57:17
              #include<stdio.h>
              int fibonacci(int n){
                  if(n==1||n==2){
                      return 1;
                  }
                      else{
                          return fibonacci(n-1)+fibonacci(n-2);
                      
                  }
              }
              int fibonacciss(int a, int b) {
                  int n = 1;
                  int count = 0;
                  while (1) {
                      int f = fibonacci(n);
                      if (f > b) {
                          break;
                      }
                      if (a <= f && f <= b) {
                          count++;
                      }
                      n++;
                  }
                  return count;
              }
              int main(){
                  int a,b;
                  scanf("%d %d",&a,&b);
                  int result=fibonacciss(a,b);
                  printf("%d",result);
              }
              
              
              • 0
                @ 2024-4-24 22:29:10
                #include <stdio.h>
                int main()
                {
                    int a=1,b=1,c=2;
                    int m,n,i=0,w;
                    scanf("%d%d",&m,&n);
                    if(a>=m)i++;
                    if(b>=m)i++;
                    for(w=1;w<=1000;w++)
                    {
                        c=a+b;
                
                        if(c>n)break;
                        else if(c>=m)i++;
                        
                        a=b;
                        b=c;
                        
                    }
                    printf("%d",i);
                    return 0;
                }//
                
                • 0
                  @ 2024-1-11 22:40:10
                  #include<stdio.h>
                  int main(){
                  	int a,b,sum=0;
                  	long long int x[30];
                  	scanf("%d %d",&a,&b);
                      x[0]=1;x[1]=1;
                      for(int i=2;i<30;i++){
                      	x[i]=x[i-1]+x[i-2];
                  	}
                  	for(int i=0;i<30;i++){
                  		if(x[i]>=a&&x[i]<=b) sum++;
                  	}
                  	printf("%d",sum);
                  	return 0;
                  } 
                  
                  • 0
                    @ 2023-10-8 19:46:38

                    #include <stdio.h> int main() { int a,b; int i,cont=0; scanf("%d %d",&a,&b); int e[100]={1,1}; for(i=2;i<100;i++) { e[i]=e[i-1]+e[i-2]; } for(i=0;i<100;i++) { if(e[i]>=a&&e[i]<=b) { cont++; }

                    }
                    printf("%d",cont);
                    return 0;
                    

                    }

                    • 0
                      @ 2023-8-23 16:37:46
                      #include<stdio.h>
                      int main(){
                          int a,b,a1,a2;
                          a1=0;
                          a2=1;
                          scanf("%d %d",&a,&b);
                          int f=0,i=0;
                               while(f<=b){
                                    f=a1+a2;
                                    int t=a2;
                                    a2=f;
                                    a1=t;
                                   if(f>=a&&f<=b)
                      			{
                      			  i++;
                      			}
                               }
                               if(a==1||b==1){
                               	i++;
                      		 }
                                    printf("%d",i);
                          return 0;
                      }
                      
                      • 1

                      信息

                      ID
                      48
                      时间
                      1000ms
                      内存
                      128MiB
                      难度
                      7
                      标签
                      递交数
                      3392
                      已通过
                      842
                      上传者