12 条题解

  • 7
    @ 2023-8-21 17:30:03

    解方程问题。

    (v1 - v2) * a = n

    (v1 + v2) * b = n;

    解出v1, v2 输出即可。

    #include <stdio.h>
    
    int main()
    {
    	int n, a, b;
    	scanf("%d %d %d", &n, &a, &b);
    	int v1 ,v2; 
    	v1 = (n / a + n / b) / 2;
    	v2 = (n / b - n / a) / 2;
        printf("%d %d",v1, v2);
        return 0;
    }
    
    • 5
      @ 2023-10-7 20:05:56

      哦豁,来看计算方式了吧👀️

      • 1
        @ 2025-8-21 18:00:03

        #include <stdio.h>

        int main(void) {

        int n, a, b;

        int m = scanf("%d %d %d", &n, &a, &b);

        long long m_1 = (long long)n * (a + b);

        long long m_2 = (long long)n * (a - b);

        long long mmm = 2LL * a * b;

        int v_1 = m_1 / mmm;

        int v_2 = m_2 / mmm;

        printf("%d %d", v_1, v_2);

        return 0;

        }

        • 1
          @ 2022-12-4 19:27:57
          #include<iostream>
          using namespace std;
          int main(){
          long long int  n,a,b;long long int v1, v2;
          cin>>n>>a>>b;
          v1=(n/a+n/b)/2.0;
          v2= (n/b-n/a)/2.0;
          cout<<v1<<' '<<v2;
              return 0;
          }
          
          • 1
            @ 2022-9-21 22:57:29
            #include<stdio.h>
            int main()
            {
            	int n,a,b;
            	
            
            
            
            
            	
            	scanf("%d%d%d",&n,&a,&b);
            
            
            
            	int v1 = (n / a + n / b) / 2;
            
            
            
            
            	
            	int v2 = n / b - v1;
            	v1 >= v2;
            	
            	
            	
            	
            	
            	printf("%d %d",v1, v2);
            	
            	
            	
            	
            	return 0;
            }
            
            • 0
              @ 2024-9-9 23:21:54

              #include<stdio.h> int main (){ int n,a,b; scanf("%d %d %d",&n,&a,&b); int v1=(n/a+n/b)/2;8 int v2=(n/b-n/a)/2; printf("%d %d",v1,v2); return 0; //不收徒,尤其115寝室和曹佳佳

              • 0
                @ 2024-4-24 21:56:52
                #include <stdio.h>
                int main()
                {
                    int a,b,c;
                    int v1,v2,n1,n2;
                    scanf("%d%d%d",&a,&b,&c);
                    n1=a/b;
                    n2=a/c;
                    v2=(n2-n1)/2;
                    v1=(n1+n2)/2;
                    printf("%d %d",v1,v2);
                    return 0;
                }////B站搜索关注Siglota喵
                
                • 0
                  @ 2023-9-23 22:07:22

                  跑道长是300

                  • 0
                    @ 2023-9-9 13:27:19

                    #include<stdio.h> int main() { int a,b,n; scanf("%d %d %d",&n,&a,&b); int j,y; n = (j-y)*a; n = (j+y)*b; printf("v1=%d v2=%d",j,y); return 0; } 为什么我这个输出的数据不正确

                    • 0
                      @ 2023-8-15 12:04:47

                      #include<stdio.h> int main() { int n,a,b; scanf("%d %d %d",&n,&a,&b); int v1,v2; v1=(n*(a+b))/(2ab); v2=(n*(a-b))/(2ab); printf("%d %d",v1,v2); return 0; }

                      • 0
                        @ 2022-11-26 21:18:52
                        #include <iostream>
                        using namespace std;
                        int main()
                        {
                            int n,a,b,v1,v2;
                            cin>>n>>a>>b;
                            cout<<(n/b+n/a)/2.0<<' '<<(n/b-n/a)/2.0<<endl;
                            return 0;
                        }
                        
                        • 0
                          @ 2022-9-18 11:39:53

                          #include <iostream> using namespace std; int main() { int n,a,b; cin>>n>>a>>b; cout<<(an+nb)/(2ab)<<" "<<(an-nb)/(2ab)<<endl; return 0;

                          }

                          • 1

                          信息

                          ID
                          8
                          时间
                          1000ms
                          内存
                          128MiB
                          难度
                          7
                          标签
                          递交数
                          13674
                          已通过
                          2942
                          上传者