9 条题解

  • 3
    @ 2023-9-23 21:20:03
    #include <stdio.h>
    int main(){
        // int 整数型,String 字符串型,float n 小数型,double 双精度型
        double r;
        double PI=3.14159;
        scanf("%lf",&r);
        printf("%.4f",r*r*PI);
        return 0;
    }
    
    • 2
      @ 2023-7-20 9:31:07
      #include <iostream>
      using namespace std;
      const double PI = 3.14159;
      double r;
      int main()
      {
          cin >> r;
          printf("%.4lf\n", r * r * PI);
      }
      
      • 1
        @ 2025-5-1 22:35:20
        #include "bits/stdc++.h"
        using namespace std;
        #define int double
        #define pai 3.14159
        signed main(){
            int r;
            cin>>r;
            printf("%.4f",pai*r*r);
            return 0;
        }
        
        • 0
          @ 2024-4-24 21:57:13
          #include <stdio.h>
          int main()
          {
              double r,s;
              scanf("%lf",&r);
              s=3.14159*r*r;
              printf("%.4lf",s);
              return 0;
          }//B站搜索关注Siglota喵
          
          • 0
            @ 2023-9-13 15:08:19
            #include<iostream>
            using namespace std;
            #include<iomanip>
            	int main(){
            	const	double p1=3.14159;
            	double r;
            	cin>>r;
            	cout<<fixed<<setprecision(4)<<p1*r*r<<endl;
            return 0;
            }
            
            • 0
              @ 2023-7-29 18:22:38
              import java.util.*;
              public class Main {
                  public static void main(String[] args) {
                      Scanner in = new Scanner(System.in);
                      double r = in.nextDouble();
                      double pi = 3.14159;
                      double s = r * r * pi;
                      System.out.printf("%.4f", s);
                  }
              }
              
              • 0
                @ 2022-9-18 11:51:37
                #include <stdio.h> 
                int main()
                {
                	double a,c;
                	scanf("%lf",&a);
                	c=a*a*3.14159;
                	printf("%.4lf",c);
                	
                	
                	return 0;
                 } 
                
                • 0
                  @ 2022-9-17 16:49:11

                  #include<stdio.h>

                  #define pi 3.14159

                  int main(){

                  double r;

                  scanf("%lf",&r);

                  printf("%.4lf",rrpi);

                  return 0;

                  }

                  • 0
                    @ 2022-9-14 9:50:50
                    #include<iostream>
                    using namespace std;
                    #include <cstdio>
                    int main() {
                        double r;
                        const double PI = 3.14159;
                        cin >> r;
                        double val = PI * r * r;
                        printf("%.4f", val);
                    }
                    
                    • 1

                    信息

                    ID
                    9
                    时间
                    1000ms
                    内存
                    128MiB
                    难度
                    7
                    标签
                    递交数
                    14300
                    已通过
                    2784
                    上传者